sin^4x+sin^2x+cos^2x=0

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Solution for sin^4x+sin^2x+cos^2x=0 equation: 


Simplifying
sin4x + sin2x + cos2x = 0

Reorder the terms:
cos2x + in2sx + in4sx = 0

Solving
cos2x + in2sx + in4sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1in2sx' to each side of the equation.
cos2x + in2sx + -1in2sx + in4sx = 0 + -1in2sx

Combine like terms: in2sx + -1in2sx = 0
cos2x + 0 + in4sx = 0 + -1in2sx
cos2x + in4sx = 0 + -1in2sx
Remove the zero:
cos2x + in4sx = -1in2sx

Add '-1in4sx' to each side of the equation.
cos2x + in4sx + -1in4sx = -1in2sx + -1in4sx

Combine like terms: in4sx + -1in4sx = 0
cos2x + 0 = -1in2sx + -1in4sx
cos2x = -1in2sx + -1in4sx

Divide each side by 'os2x'.
c = -1in2o-1s-1 + -1in4o-1s-1

Simplifying
c = -1in2o-1s-1 + -1in4o-1s-1

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